Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A rock is dropped from the top of a 2000-foot building. After 1 second, the rock is traveling 32 feet per second. After 2 seconds, the rock
is traveling 64 feet per second. Let y be the rate of descent and be the number of seconds since the rock was dropped.
a. Write a linear equation that relates time x to rate y. (Hint: Use the ordered pairs (1,32) and (2,64).]
b. Use this equation to determine the rate of travel of the rock 15 seconds after it was droppedwas dropped.
Thank

A Rock Is Dropped From The Top Of A 2000foot Building After 1 Second The Rock Is Traveling 32 Feet Per Second After 2 Seconds The Rock Is Traveling 64 Feet Per class=

Sagot :

musiclover10045

Using the pairs (1,32) and (2,64) the rate of speed is (64-32 / 2-1 = 32 feet per second.

To find the rate of decent you would multiply the rate by time:

The equation is y = 32x

B. Replace x with 15 and solve for y:

Y = 32(15)

Y = 480

The rate of speed is 480 feet per second.

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.