At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

9.
The dimensions of a rectangle are x cm and (x + 9 )cm. If the area of the rectangle is 52 cm?,
calculate the only possible value of x.


Sagot :

Answer:

Answer 4

width = 4

Length = 13

Step-by-step explanation:

Givens

Length = x + 9

width = x

Area = 52

Equation

Area = L * W

Area = x (x + 9 )  = 52

Solution

x (x + 9) = 52            remove the brackets

x^2 + 9x = 52           Subtract 52 from both sides

x^2 + 9x - 52 = 0     Factor

(x + 13)(x - 4) = 0

x + 13 is an extraneous solution. You cannot have a length or width of - 13 or minus anything for that matter.

x - 4 = 0                    Add 4 to both sides

x = 4                         This is the only possible solution.