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The position-time equation for a cheetah chasing an antelope is:
xf = 1.6m + (1.7m/s2)t2
(a) What is the initial position of the cheetah?
(b) What is the initial velocity of the cheetah?
(c) What is the cheetah's acceleration?
(d) What is the position of the cheetah at t = 4.4s?

Sagot :

Answer:

x = 1.6 + 1.7 t^2      omitting signs

a) at t = 0     x = 1.6 m

b) V = d x / d t = 3.4 t

at t = 0     V = 0

c) A = d^2 x / d t^2 = 3.4     (at t = 0  A = 3.4 m/s^2)

d)  x = 1.6 + 1.7 * (4.4)^2 = 34.5    (position at 4.4 sec = 34.5 m)

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