maddylane111
Answered

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Force between two bodies having charges 5.0 x 102 uC and 1.0 x 102 uC separated by
distance of 0.50 m in air is
1.0 x 103N
0 3.0 x 102 N
1800 N
O2200 N

Force Between Two Bodies Having Charges 50 X 102 UC And 10 X 102 UC Separated By Distance Of 050 M In Air Is 10 X 103N 0 30 X 102 N 1800 N O2200 N class=

Sagot :

VirαtKσhli

Answer:

1800 N

Explanation:

We know that ,

[tex]\longrightarrow\sf Force = k \dfrac{q_1 q_2}{r^2}\\ [/tex]

[tex]\longrightarrow\sf Force = \dfrac{ 9 * 10^9 * 5 * 10^2 * 1 * 10^2 * 10 ^{-12}}{ ( 0.5)^2}\\[/tex]

[tex]\longrightarrow\sf Force = \dfrac{ 9 * 10^9 * 5 * 10^2 * 1 * 10^2 * 10 ^{-12}}{ 25 * 10^{-2}}[/tex]

[tex]\longrightarrow\sf Force = 1800 \ N \\\\[/tex]

** Edits are welcomed **

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