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Sagot :
Las cuatro carreras saldrán juntas después de 1 hora = 8:00 a.m.
Primera ejecución = 10
Segunda ejecución = 12
Tercera carrera = 15
Cuarta carrera = 30
Dado que las cuatro carreras salieron juntas a las 7:00 a.m. del lunes;
Para calcular el tiempo que los cuatro volverán a funcionar juntos,
Calculamos el mínimo común múltiplo de los cuatro:
Múltiplos de:
10:10, 20, 30, 40, 50, 60, 70, 80, 90
12:12, 24, 36, 48, 60, 72, 84, 96, 108
15:15, 30, 45, 60, 75, 90, 105
30:30, 60, 90, 120, 150, 180, 210
El mínimo común múltiplo de 10, 12, 15 y 30 es 60.
Por lo tanto, las cuatro carreras volverán a salir después de 60 minutos, que es:
60 minutos = 1 hora
7:00 a.m + 1 hora = 8:00 a.m
Más información: https://brainly.com/question/24560329
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