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vz = 24 m/s , Vy = 39 m/s. Find the vector's direction.

Sagot :

Explanation:

The vector's direction is given by

[tex]\tan{\theta} = \dfrac{v_y}{v_x} = \dfrac{39\:\text{m/s}}{24\:\text{m/s}}[/tex]

[tex]\:\:\:\:\:\:\:= 1.625[/tex]

or

[tex]\theta = \tan^{-1}(1.625) = 58.4°[/tex] with respect to the +x-axis.

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