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Write the equation of the line that passes through (4,-3) and (8,-12)

Sagot :

devishri1977

Answer:

Step-by-step explanation:

(4 , -3)   ;  (8 , -12)

[tex]Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\dfrac{-12-[-3]}{8-4}\\\\=\dfrac{-12+3}{4}\\\\=\dfrac{-9}{4}[/tex]

m = -9/4 ; (4 , -3)

[tex]y - y_{1}= m(x -x_{1}\\\\y - [-3]= \dfrac{-9}{4}(x -4)\\\\\\y + 3 = \dfrac{-9}{4}x -4*\dfrac{-9}{4}\\\\\\y + 3 =\dfrac{-9}{4}x+9\\\\\\y = \dfrac{-9}{4}x+9-3\\\\y=\dfrac{-9}{4}x+6[/tex]

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