Answered

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Simplify 16x² - 9y²/(4x-3y)^2​

Sagot :

sqdancefan

9514 1404 393

Answer:

  (4x +3y)/(4x -3y)

Step-by-step explanation:

  [tex]\dfrac{16x^2-9y^2}{(4x -3y)^2}=\dfrac{(4x)^2-(3y)^2}{(4x-3y)^2}=\dfrac{(4x-3y)(4x+3y)}{(4x-3y)(4x-3y)}\\\\=\boxed{\dfrac{4x+3y}{4x-3y}}[/tex]

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