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Sagot :
2x - 3y = 6
-3y = 6 - 2x
y = (6-2x)/(-3)
y = 6/-3 - 2x / -3
y = -2 + (2/3)x
Explaination :
Given equation,
- 2x - 3y = 6
Our aim is to solve the given equation and get out the value of y.
Transposing the 2x which is in L.H.S. to R.H.S.,
[tex]\implies \: \displaystyle{ \sf{2x - 3y = 6}} \\ \\ \implies \: \displaystyle{ \sf{- 3y \: = \: 6 - 2x}} \\ \\ \implies \: \displaystyle{ \sf{3y \: = \: 2x - 6}}[/tex]
Dividing the R.H.S. with 3,
[tex]\implies \: \displaystyle{\sf{y \: = \: \dfrac{2x - 6}{3}}} \\ \\ \implies \: \displaystyle{ \red{\bf{y \: = \: \dfrac{2x}{3} \: - \: \dfrac{6}{3} }}}[/tex]
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