Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Taking logarithms and antilogarithms is necessary to solve many chemistry problems. For practice,
complete the following table, where N is a number.
N
In N
log N
8.99
3.949
0.134
Submit Answer

Taking Logarithms And Antilogarithms Is Necessary To Solve Many Chemistry Problems For Practice Complete The Following Table Where N Is A Number N In N Log N 89 class=

Sagot :

pstnonsonjoku

The values of N, log N and ln N are all worked out below.

We have the number N as 8.99

hence;

1) lnN = ln(8.99) = 2.196

log N = log (8.99) = 0.954

2) If we have ln N as 3.949

N = e^3.949 = 51.88

So;

log N = log (51.88) = 1.715

3) log N = 0.134

N = Antilog (0.134 ) = 1.36

ln N = ln (1.36) = 0.307

Learn more: https://brainly.com/question/4210362

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.