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Sagot :
Answer:
- 200 cc
Step-by-step explanation:
Let x be the added 20% solution.
The salt content is same:
- 50*0.6 + x*0.2 = 0.28*(x + 50)
- 30 + 0.2x = 0.28x + 14
- 0.28x - 0.2x = 30 - 14
- 0.08x = 16
- x = 16/0.08
- x = 200
Let added amount be y .
- The salt remains same
[tex]\\ \tt\Rrightarrow 50(0.6)+0.2y=0.28(y+50)[/tex]
[tex]\\ \tt\Rrightarrow 0.2y+30=0.28y+14[/tex]
[tex]\\ \tt\Rrightarrow 0.2y-0.28y=14-30[/tex]
[tex]\\ \tt\Rrightarrow -0.08y=-16[/tex]
[tex]\\ \tt\Rrightarrow 0.08y=16[/tex]
[tex]\\ \tt\Rrightarrow y=\dfrac{16}{0.08}[/tex]
[tex]\\ \tt\Rrightarrow y=200[/tex]
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