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Sagot :
[tex]\\ \tt\Rrightarrow sin\Theta=\dfrac{\sqrt{3}}{2}[/tex]
[tex]\\ \tt\Rrightarrow cosec\Theta=\dfrac{2}{\sqrt{3}}[/tex]
Now
[tex]\\ \tt\Rrightarrow cos\Theta=\sqrt{1-sin^2\Theta}= \sqrt{1-\left(\dfrac{\sqrt{3}}{2}\right)^2}=\sqrt{1-\dfrac{3}{4}}=\sqrt{\dfrac{4-3}{4}}=\sqrt{\dfrac{1}{4}}=\dfrac{1}{2}[/tex]
[tex]\\ \tt\Rrightarrow sec\Theta=2[/tex]
Now
[tex]\\ \tt\Rrightarrow tan\Theta=\dfrac{sin\Theta}{cos\Theta}[/tex]
[tex]\\ \tt\Rrightarrow tan\Theta=\dfrac{\dfrac{\sqrt{3}}{2}}{\dfrac{1}{2}}=\sqrt{3}[/tex]
[tex]\\ \tt\Rrightarrow cot\Theta=\dfrac{1}{\sqrt{3}}[/tex]
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