Answered

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The concentration of a drug in an organ at any time t (in seconds) is given by
C(t) =
0.25 - 15(1 - e-t/60) if Osts 20
15e-t/60 - 10e-(t - 20)/60 if t > 20
where C(t) is measured in milligrams per cubic centimeter (mg/cm3).
(a) What is the initial concentration of the drug in the organ?
0
mg/cm3
(b) What is the concentration of the drug in the organ after 10 sec? (Round your answer to three decimal places.)
mg/cm
the organ after 26 sec? (Round your answer to three decimal places.)
(c) What is the concentration of the drug
mg/cm3

Sagot :

joshirabindra579

Answer:

The concentration of a drug in an organ at any time t (in seconds) is given by s 0.25t - 15(1 - e-t/60) if osts 20 | 15e-t/60 – 10e-(t - 20)/60 if t> 20 where c(t) is measured in milligrams per cubic centimeter (mg/cm3). (a) What is the initial concentration of the drug in the organ? 0 mg/cm3 (b) What is the concentration of the drug in the organ after 14 sec? (Round your answer to three decimal places.) x mg/cm3 38 (c) What is the concentration of the drug in the organ after 40 sec? (Round your answer to three decimal places.) mg/cm3 Need Help? | Read It

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