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Town A and Town B are 100 km apart.
At 0800, James departs for Town B from
Town A, driving at a constant speed of
60 km/h. At 0830, Kumar departs for Town A
from Town B, driving at a constant speed of
50 km/h along the same route. What time
will James and Kumar pass each other?

Please help, thank you!

Sagot :

Distance between them=100km

James started at 8:00 and Kumar at 8:30

Time difference=30min

Now apply physics

Time=30min

Speed=60km/h

[tex]\\ \rm\longmapsto Distance=Speed(Time)[/tex]

[tex]\\ \rm\longmapsto Distance=60\times \dfrac{1}{2}h=30km[/tex]

Now

Distance left =100km-30km=70km

Again

Distance=70km

Speed=60+50=110km/h

[tex]\\ \rm\longmapsto Time=\dfrac{Distance}{Speed}=\dfrac{70}{110}\approx38min[/tex]

Now assumed time=8:30+0:38=9:08(approx)

Both will cross each other at 9:08

mhanifa

Answer:

  • 09 : 08 : 12

Step-by-step explanation:

James travels 30 min before Kumar starts to travel.

By this time James travels:

  • 60 km/h *30 min =
  • 60 km/h * 0.5 h = 30 km

At 8:30 the distance between them is:

  • 100 km - 30 km = 70 km

Time to travel 70 by both:

  • 70 km / (60 + 50) km/h =
  • 70 /110 h =
  • 7/11 h ≈ 38.2 min

James and Kumar pass each other at:

  • 08:30 + 38.2 =
  • 09: 08.2

or

  • 09 : 08 : 12
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