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Calculate the side lengths a and b to two decimal places.

A. a = 11.40 and b= 13.38
B. a = 11 and b = 15
C. a = 4.18 and b = 3.15
D. a = 10.92 and b= 14.52

Calculate The Side Lengths A And B To Two Decimal Places A A 1140 And B 1338 B A 11 And B 15 C A 418 And B 315 D A 1092 And B 1452 class=

Sagot :

matshovhanapaul

Answer:

A.)=24.78

B.)=26

C.)=7.33

D.)=25.44

Step-by-step explanation:

A.)11.40+13.38=24.78

B.)11+15=26

C.)4.18+3.15=7.33

D.)10.92+14.52=25.44

Answer:

D

Step-by-step explanation:

Using the Sine rule to find a and b

We require to find ∠ C

∠ C = 180° - (115 + 43)° = 180° - 158° = 22°

Then

[tex]\frac{a}{sinA}[/tex] = [tex]\frac{c}{sinC}[/tex] , substitute values

[tex]\frac{a}{sin43}[/tex] = [tex]\frac{6}{sin22}[/tex] ( cross- multiply )

a × sin22° = 6 × sin43° ( divide both sides by sin22° )

a = [tex]\frac{6sin43}{sin22}[/tex] ≈ 10.92 ( to 2 dec. places )

---------------------------------------------------------

[tex]\frac{b}{sinB}[/tex] = [tex]\frac{c}{sinC}[/tex] , that is

[tex]\frac{b}{sin115}[/tex] = [tex]\frac{6}{sin22}[/tex] ( cross- multiply )

b × sin22° = 6 × sin115° ( divide both sides by sin22° )

b = [tex]\frac{6sin115}{sin22}[/tex] ≈ 14.52 ( to 2 dec. places )

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