Answered

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3x^2-2x(x+1)=x^2+x-6

Sagot :

Answer:

x = 2

Step-by-step explanation:

3x² - 2x(x + 1) = x² + x - 6 ← distribute and simplify left side

3x² - 2x² - 2x = x² + x - 6

x² - 2x = x² + x - 6 ( subtract x² + x from both sides )

- 3x = - 6 ( divide both sides by - 3 )

x = 2

yashonamaharjan5

Step-by-step explanation:

3x^2-2x(x+1) = x^2 +x-6

3x^2−2x(+1)=x^2+xx−6

3x^2−2x^2−2x=x^2+x−6

3x^2−2x^2-2x=x^2+x−6

1x^2-2x=x^2+x-6

1x^2−2x=x^2+x−6

x^2−2x=x^2+−6

solution:

x=2

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