sukriti009
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Guys please answer this question best one with explanation will get brainiest and 5 start compete yourself with other
no 5 one there is answer but how that came

Guys Please Answer This Question Best One With Explanation Will Get Brainiest And 5 Start Compete Yourself With Other No 5 One There Is Answer But How That Came class=

Sagot :

discipulus

Answer:

[tex] {( \sin(a) + \cos(a) )}^{2} + \\ {( \sin(a) - \cos(a) )}^{2} \\ {(a + b})^{2} = {a}^{2} + 2ab + {b}^{2} \\ {(a - b})^{2} = {a}^{2} - 2ab + {b}^{2} [/tex]

[tex]

{(\sin(a)+ \cos(b)})^{2} = \\{\sin(a)}^{2} + 2\sin(a)\cos(b)\\ + {\cos(b)}^{2} \\ {(\sin(a) - \cos(b)})^{2} = \\{\sin(a)}^{2} - 2\sin(a)\cos(b) + {\cos(b)}^{2} [/tex]

[tex] 2\sin(a)\cos(b) cancel :\ out\\[/tex]

[tex] =2{\sin}^{2}(a) +2{\cos}^{2}(a) [/tex]

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.