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Một vật dao động điều hòa theo phương trình x=4cos(2pit-2pi/3) xác định trạng thái dao động tại thời điểm ban đầu ba và trạng thái dao động tại thời điểm tê bằng 2,75s

Sagot :

Answer:

Explanation:

y = Acos(ωt + φ)

ω = 2π

φ = -2π/3

A = 4

v = -ωAsin(ωt + φ)

a = -ω²Acos(ωt + φ)

y(0) = 4cos(-2π/3) = -2 m

v(0) = -2π(4)sin(-2π/3) = -21.77 m/s

a(0) = -(2π)²(4)cos(-2π/3) = 78.96 m/s²

y(2,75) = 4cos(2π(2,75) - 2π/3) = -3.46 m

v(2,75) = -2π(4)sin(2π(2,75) - 2π/3) = -12.57 m/s

a(2,75) = -(2π)²(4)cos(2π(2,75) - 2π/3) = 136.76m/s²

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