Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

A van is traveling with an initial velocity of 12 m/s. The driver takes a time of 45 seconds to speed up to a velocity of 20 m/s. How much distance did the van cover during this time?

Sagot :

  • Initial velocity=u=12m/s
  • Final velocity=v=20m/s
  • Time=t=45s

[tex]\\ \rm\hookrightarrow Acceleration=\dfrac{v-u}{t}[/tex]

[tex]\\ \rm\hookrightarrow Acceleration=\dfrac{20-12}{45}[/tex]

[tex]\\ \rm\hookrightarrow Acceleration=\dfrac{8}{45}[/tex]

[tex]\\ \rm\hookrightarrow Acceleration=0.1m/s^2[/tex]

Now

  • Distance=s

[tex]\\ \rm\hookrightarrow v^2-u^2=2as[/tex]

[tex]\\ \rm\hookrightarrow (20)^2-12^2=2(0.1)s[/tex]

[tex]\\ \rm\hookrightarrow 400-144=0.2s[/tex]

[tex]\\ \rm\hookrightarrow 256=0.2s[/tex]

[tex]\\ \rm\hookrightarrow s=\dfrac{256}{0.2}[/tex]

[tex]\\ \rm\hookrightarrow s=1280m[/tex]

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.