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Sagot :
The force acting on an object is the product of mass and the object's acceleration.
The acceleration of the piano is 15.0m/s^2
Given that:
[tex]F_A = 300N\\[/tex]-- Amirah
[tex]F_D =200N[/tex] -- Dana
[tex]F_f = -230N[/tex] --- the frictional force
[tex]W = 180N[/tex] --- the piano's weight
First, we calculate the net force pushing the piano
[tex]F = F_A + F_D + F_f[/tex]
So, we have:
[tex]F = 300N + 200N -230N[/tex]
[tex]F = 270N[/tex]
Next, we calculate the mass of the piano
[tex]W = mg[/tex]
Make m the subject
[tex]m = \frac Wg[/tex]
So, we have:
[tex]m = \frac{180}{10}[/tex]
[tex]m = 18[/tex]
The force acting on an object is calculated as:
[tex]F = ma[/tex]
Substitute values for F and m
[tex]270 = 18 \times a[/tex]
Divide through by 18
[tex]15 = a[/tex]
[tex]a = 15[/tex]
Hence, the acceleration of the piano is 15.0m/s^2
Read more about force and acceleration at:
https://brainly.com/question/20511022
The acceleration is a transition in an object's motion or speed over a time. It can be determined by splitting the velocity change so over total time. In brief, it is a percentage at which speed changes over time, to regard to direction and speed.
Given:
Force apply by Amirah [tex]\bold{F_A = 300\ N}[/tex]
Force apply by Dana [tex]\bold{ F_D=200\ N}[/tex]
Frictional force [tex]\bold{ F_f=-230\ N}[/tex]
Weight of piano [tex]\bold{W=180\ N}[/tex]
Calculating all the forces:
[tex]\to \bold{F=F_A+F_D+F_f}[/tex]
[tex]\bold{=300N+200N-230N}\\\\ \bold{=500N-230N}\\\\ \bold{=270N}[/tex]
Calculating the weight of piano:
[tex]\to \bold{W=mg} \\\\\to \bold{m=\frac{W}{g}}\\\\\to \bold{m=\frac{180}{10}=18}[/tex]
Calculating the force which is apply on the object:
[tex]\to \bold{F=ma}[/tex]
[tex]\to \bold{270=18 \times a}\\\\ \to \bold{a=\frac{270}{18}}\\\\ \to \bold{a=15 \ \frac{m}{s^2}}\\\\[/tex]
Therefore the, the acceleration of the piano is [tex]\bold{15.0\ \frac{m}{s^2}}[/tex]
Learn more:
brainly.com/question/4514563
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