Answered

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A 1.200kg block of phosphorus-32, which has a half life of 14.3 days, is stored for 100.1 days. At the end of this period, how much phosphorus-32 remains? and show how did u solve it

Sagot :

Answer:

100.1 days / (14.3 days/half-life) = 7 half-lives

(1/2)^7 = .00781    amount left after 7 half-lives

1200 kg ^ .00781 = 9.38 kg

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