jupiterbhanot
Answered

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A car slows down from 21 m/s to rest in a distance of 63m. Assuming the car has a constant acceleration, calculate the time it took to come to a stop.

Sagot :

VirαtKσhli

Answer:

-3.5 m/s²

Explanation:

  • Initial Velocity = 21m /s
  • Final velocity = 0m/s
  • Distance = 63 m .
  • Acclⁿ = ?

We know that :-

[tex]\longrightarrow [/tex] Stopping distance = u²/2(-a)

[tex]\longrightarrow [/tex] 63m = (21m/s)² / -2a

[tex]\longrightarrow [/tex] a = - 21 * 21 / 63 * 2 m/s²

[tex]\longrightarrow [/tex] a = - 3.5 m/s²

**Edits are welcomed**

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