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The height of a trapezium of area 162 cm^2 is 6cm. if one of the base is 23 cm. find the other

Sagot :

Answer:

31 cm

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = [tex]\frac{1}{2}[/tex] h (a + b)

where h is the height and a, b the bases

Here A = 162, h = 6 and a = 23 , then

[tex]\frac{1}{2}[/tex] × 6 (23 + b) = 162

3(23 + b) = 162 ( divide both sides by 3 )

23 + b = 54 ( subtract 23 from both sides )

b = 31

The other base is 31 cm

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