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Sagot :
The relative velocity of the athlete relative to the ground is 5.2 m/s
The given parameters;
constant velocity of the athlete, V = 5.2 m/s
let the velocity of the ground = Vg = 0
The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.
The athlete is the moving object in this question while the ground is stationary.
The relative velocity of the athlete relative to the ground is calculated as follows;
[tex]V/V_g = V - V_g = 5.2 - 0 = 5.2 \ m/s[/tex]
Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s
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