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Write and solve an equation to find the number n.
Eight plus the quotient of a number and 3 is -2.
Equation: = -2
The number is n=

Sagot :

The required equation is [tex]8+\dfrac{n}{3}=-2[/tex] and the required unknown number is [tex]n=-30[/tex].

Given:

The statement is "Eight plus the quotient of a number and 3 is -2".

To find:

The required equation and the value of the variable [tex]n[/tex].

Solution:

Let [tex]n[/tex] be the unknown number.

Quotient of a number and 3 is [tex]\dfrac{n}{3}[/tex].

Eight plus the quotient of a number and 3 is [tex]8+\dfrac{n}{3}[/tex].

It is given that eight plus the quotient of a number and 3 is -2. So,

[tex]8+\dfrac{n}{3}=-2[/tex]

The required equation is [tex]8+\dfrac{n}{3}=-2[/tex]

Multiply both sides by 3.

[tex]24+n=-6[/tex]

Subtracting 24 from both sides, we get

[tex]24+n-24=-6-24[/tex]

[tex]n=-30[/tex]

The required unknown number is [tex]n=-30[/tex].

Learn more:

https://brainly.com/question/17466495

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