Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

what is the center and radius of the circle defined by the equation (x-4)^2+(y-7)^2=49

Sagot :

Answers:

Center = (4, 7)

Radius = 7

===========================================================

Explanation:

The general template of any circle is

(x-h)^2 + (y-k)^2 = r^2

This general circle has these properties:

  • Center = (h,k)
  • Radius = r

Based on the equation your teacher gave you, we see that

  • h = 4
  • k = 7
  • r = 7, since 7^2 = 7*7 = 49

Therefore, this circle has center = (4,7) and radius = 7

Side note: The center's y coordinate and radius aren't always the same value.

Answer:

center (4,7)

radius 7

Step-by-step explanation:

The number in the parentheses with the x and with the y tell you the center of the circle is at 4, 7. The other side of the equation is 49, which is r squared. So the radius is 7

Per Khan academy:

The general equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius