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Decide what values of the variable cannot be solutions for each equation.
[tex]\frac{1}{4x} - \frac{2}{x} = 3[/tex]


Sagot :

Step-by-step explanation:

[tex] \frac{1}{4x} - \frac{2}{x} = 3 \\ \frac{1}{4x} - \frac{2}{x} \times \frac{4}{4} = 3 \\ \frac{1}{4x} - \frac{8}{4x} = 3 \\ \frac{1 - 8}{4x} = 3 \\ \frac{ - 7}{4x} = 3 \\ 4x = \frac{ - 7}{3} \\ x = \frac{ - 7}{12} \\ thank \: you[/tex]

Answer:

[tex]→ \frac{1}{4x} - \frac{2}{x} = 3 \\ \frac{1}{4x} - \frac{(2 \times 4)}{(x \times 4)} = 3 \\ \frac{1}{4x} - \frac{8}{4x} = 3 \\ \frac{(1 - 8)}{4x} = 3 \\ \frac{( - 7)}{4x} = 3 \\ \frac{1}{x}= \frac{(3 \times 4)}{( - 7)} \\ \frac{1}{x}= \frac{12}{( - 7)} \\ \boxed{x = \frac{( - 7)}{12} }[/tex]

  • x = -7/12 is the right answer.