zwgoosebumps
Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Please do your best, thank you so much brainliest and points

Please Do Your Best Thank You So Much Brainliest And Points class=

Sagot :

semsee45

Answer:

[tex]\textsf{A.} \quad \left(- \infty, -\dfrac{11}{3}\right][/tex]

Step-by-step explanation:

Given inequality:

[tex]\dfrac{6x+2}{5}-\dfrac{3x-7}{9} \leq -2[/tex]

Make the denominators of both fractions the same:

[tex]\implies \dfrac{9(6x+2)}{9 \cdot 5}-\dfrac{5(3x-7)}{9 \cdot 5} \leq -2[/tex]

[tex]\implies \dfrac{54x+18}{45}-\dfrac{15x-35}{45} \leq -2[/tex]

Combine the fractions:

[tex]\implies \dfrac{54x+18-(15x-35)}{45} \leq -2[/tex]

[tex]\implies \dfrac{54x+18-15x+35}{45} \leq -2[/tex]

[tex]\implies \dfrac{39x+53}{45} \leq -2[/tex]

Multiply both sides by 45:

[tex]\implies 39x+53\leq -90[/tex]

Subtract 53 from both sides:

[tex]\implies 39x\leq -143[/tex]

Divide both sides by 39:

[tex]\implies x\leq -\dfrac{11}{3}[/tex]

Therefore, the solution set is:

[tex]\left(- \infty, -\dfrac{11}{3}\right][/tex]

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.