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at a cost of $1600/oz, how much would you have to pay for a solid cubic foot of gold?

useful information: (1 oz = 28.4 g; 1 in = 2.54 cm)

Sagot :

Eduard22sly

You will pay $ 30876800

We'll begin by calculating the mass in ounce (oz) of a cube foot (ft³) of gold. This can be obtained as follow:

Density of gold = 19298 oz/ft³

Volume of gold = 1 ft³

Mass of gold =?

Density = mass /volume

19298 = mass / 1

Mass of gold = 19298 oz

Finally, we shall determine the cost of 19298 oz of gold. This can be obtained as follow:

1 oz = $ 1600

Therefore,

19298 oz = 19298 × 1600

19298 oz = $ 30876800

Therefore, a solid cube foot of gold (i.e 19298 oz) will cost $ 30876800

Learn more: https://brainly.com/question/15407624

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