Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Mr. Kent drove to a conference. The first half in distance of the trip took 3 hours due to traffic. Traffic let up for the second half of the trip and he was able to increase his average speed by 20 mph to make sure he got there in time. Find his average rates of speed for each half of the trip if he traveled for two hours at the second rate.

Sagot :

fichoh

The travel rates are :

  • With traffic = 40 mph
  • Without traffic = 60 mph

Recall :

Distance = speed × time

With traffic :

Time taken = 3 hours

Average speed = d

Distance = 3 × d = 3d ---(1)

Without traffic :

Time taken = 2 hours

Average Speed = 20 + d

Distance = 2(20 + d) - - - (2)

Equating (1) and (2)

3d = 2(20 + d)

3d = 40 + 2d

3d - 2d = 40

d = 40

The rates for each half :

With traffic = 40 mph

Without traffic = 40 + 20 = 60 mph

Learn more : https://brainly.com/question/18796573

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.