Flowerpower2321
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

-20t^5u^2v^3
———————-
48t^7u^4v

20t5u2v3 48t7u4v class=

Sagot :

Happil

Answer:

B. [tex]\frac{-5v^2}{12t^2u^2}\\[/tex]

Step-by-step explanation:

Recall:

[tex]\frac{a^x}{a^y} = a^{x -y}\\[/tex]

[tex]a^{-x} = \frac{1}{a^x}\\[/tex]

Solution:

[tex]\frac{-20t^5u^2v^3}{48t^7u^4v} \\ \frac{-20}{48} \cdot t^{5 -7} u^{2 -4} v^{3 -1} \\ -\frac{5}{12} \cdot t^{-2} u^{-2} v^2 \\ -\frac{5v^2}{12t^2u^2}[/tex]

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.