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-20÷5(-3)+4(-2)(-1)-4²
step by step please and thank you!​

Sagot :

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

[tex] \large \tt \: -20 \div 5(-3)+4(-2)(-1)-4 ^ { 2 }[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex] \tt \: -20 \div 5(-3)+4(-2)(-1)-4 ^ { 2 }[/tex]

Divide -20 by 5 to get -4.

[tex] \tt \: -4\left(-3\right)+4\left(-2\right)\left(-1\right)-4^{2} [/tex]

Multiply -4 and -3 to get 12.

[tex] \tt \: 12+4\left(-2\right)\left(-1\right)-4^{2} [/tex]

Multiply 4 and -2 to get -8.

[tex] \tt \: 12-8\left(-1\right)-4^{2} [/tex]

Multiply -8 and -1 to get 8.

[tex] \tt \: 12+8-4^{2} [/tex]

Add 12 and 8 to get 20.

[tex] \tt \: 20-4^{2} [/tex]

Calculate 4 to the power of 2 and get 16.

[tex] \tt \: 20-16 [/tex]

Subtract 16 from 20 to get 4.

[tex] = \boxed{\boxed{ \bf 4}}[/tex]

Hey there!

-20 ÷ 5 (-3) + 4 (-2) (-1) - 4²

= -4 × -3 + 4 (-2) (-1) - 16

= 12 -8 (-1) - 16

= 12 + 8 - 16

= 20 - 16

= 4.

Hope it helps ya!