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If m < PQS = 3x+13 and m < SQT = 6x-2 what is m < PQT

Sagot :

MrRoyal

The given angles mean that line QT divides angle PQS.

The measure of [tex]\angle PQT[/tex] is [tex]15- 3x[/tex]

Given that:

[tex]\angle PQS = 3x + 13[/tex]

[tex]\angle SQT = 6x -2[/tex]

Since QT divides [tex]\angle PQS[/tex];

The equation to calculate [tex]\angle PQT[/tex] is:

[tex]\angle PQT = \angle PQS - \angle SQT[/tex]

This gives

[tex]\angle PQT = 3x + 13- (6x -2)[/tex]

Open bracket

[tex]\angle PQT = 3x + 13- 6x +2[/tex]

Collect like terms

[tex]\angle PQT = 13+2- 6x + 3x[/tex]

[tex]\angle PQT = 15- 3x[/tex]

Hence, the measure of [tex]\angle PQT[/tex] is [tex]15- 3x[/tex]

Read more about angles at:

https://brainly.com/question/13954458

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