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(Read the paragraph and answer the questions follows) The maximum amount of solute that can be dissolved in a fix amount of solvent at a fix temperature is called solubility. On the basis of amount of solute dissolved in solution, there are three types of solutions- i. supersaturated, ii. saturated and iii. saturated solutions. Supersaturated solutions contains more amount of solute than solubility. Saturated solutions has amount of solute equal to the solubility but unsaturated solutions has less than solubility. Supersaturated solutions are unstable and convert into saturated solutions by precipitation. Unsaturated solutions can be converted into saturated by evaporation of solvent. A). If solubility of a solute 'X' in water is 29 g/Litre, 2.9 g/Litre solution of solute 'X' in water is called- * 2 points Saturated Supersaturated unsaturated semisaturated 8) B). If solubility of another solute 'Y' in water is 2.9 g/Litre, saturated solution of it should contain _____ g solute in ________ mL solution. * 2 points 29, 50,000 19, 1000 1.45, 500 2.9, 50,00 This is a required question 8) C). 20 g solute is dissolved in 50 g of solution. Calculate the mass % of solution. * 2 points 20% 50% 40% 25%
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(A) The solution X is unsaturated

(B) The solution Y should contain 2.9 g solute in 1000 mL solution.

(C) The percentage by mass of the solute is 40%

(A) The type of solution X is determined as follows;

The maximum amount of solute that can dissolve in solution  X  =  29 g/Liter

The amount of solute in solution X = 2.9 g/Liter

This solution is unsaturated because the amount of solute present is less than the maximum the solution can take.

(B) The amount solute and volume in the solution Y is calculated as follows;

The solubility = 2.9 g/Liter

[tex]solubility = \frac{2.9 \ g}{L} \times \frac{L}{ mL \times 1000} = \frac{2.9 \ g}{1000mL}[/tex]

Thus, the solution should contain 2.9 g solute in 1000 mL solution.

(C) The percentage by mass of the solute is calculated as;

[tex]mass \ \% = \frac{20 \ g}{50 \ g} \times 100 \% = 40 \%[/tex]

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