Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
(A) The solution X is unsaturated
(B) The solution Y should contain 2.9 g solute in 1000 mL solution.
(C) The percentage by mass of the solute is 40%
(A) The type of solution X is determined as follows;
The maximum amount of solute that can dissolve in solution X = 29 g/Liter
The amount of solute in solution X = 2.9 g/Liter
This solution is unsaturated because the amount of solute present is less than the maximum the solution can take.
(B) The amount solute and volume in the solution Y is calculated as follows;
The solubility = 2.9 g/Liter
[tex]solubility = \frac{2.9 \ g}{L} \times \frac{L}{ mL \times 1000} = \frac{2.9 \ g}{1000mL}[/tex]
Thus, the solution should contain 2.9 g solute in 1000 mL solution.
(C) The percentage by mass of the solute is calculated as;
[tex]mass \ \% = \frac{20 \ g}{50 \ g} \times 100 \% = 40 \%[/tex]
Learn more here: https://brainly.com/question/16694555
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.