Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
(A) The solution X is unsaturated
(B) The solution Y should contain 2.9 g solute in 1000 mL solution.
(C) The percentage by mass of the solute is 40%
(A) The type of solution X is determined as follows;
The maximum amount of solute that can dissolve in solution X = 29 g/Liter
The amount of solute in solution X = 2.9 g/Liter
This solution is unsaturated because the amount of solute present is less than the maximum the solution can take.
(B) The amount solute and volume in the solution Y is calculated as follows;
The solubility = 2.9 g/Liter
[tex]solubility = \frac{2.9 \ g}{L} \times \frac{L}{ mL \times 1000} = \frac{2.9 \ g}{1000mL}[/tex]
Thus, the solution should contain 2.9 g solute in 1000 mL solution.
(C) The percentage by mass of the solute is calculated as;
[tex]mass \ \% = \frac{20 \ g}{50 \ g} \times 100 \% = 40 \%[/tex]
Learn more here: https://brainly.com/question/16694555
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.