Answered

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Write an equation for the line perpendicular to y=1/3x-2 and passing through the point (3,3)

Sagot :

Eyadaqrabawi

line given slope = x coefficient = 1/3

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

line slope (m) = -3

line equation formula = y = mx + b

y = -3x + b

from the point given

x = 3

y= 3

3 = -9 + b

b = 12

y = -3x + 12

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