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what is 5r^(2)-14r+ 8 =
in general trinomial

Sagot :

Answer:

STEP

1

:

Equation at the end of step 1

(5r2 - 14r) + 8

Step-2 : Find two factors of 40 whose sum equals the coefficient of the middle term, which is -14 .

-40 + -1 = -41

-20 + -2 = -22

-10 + -4 = -14 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -10 and -4

5r2 - 10r - 4r - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

5r • (r-2)

Add up the last 2 terms, pulling out common factors :

4 • (r-2)

Step-5 : Add up the four terms of step 4 :

(5r-4) • (r-2)

Which is the desired factorization

Final result :

(r - 2) • (5r -4)

5r^2-14r+8 is the awnser