sukriti009
Answered

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Find the product of : (4sinθ + 3cosθ) (4sinθ – 3cosθ)

Sagot :

Eyadaqrabawi

Step-by-step explanation:

(4sin0 × 4sin0) +(4sin0 × -3cos0)+ (3cos0×4sin0) +(3cos0 × -3cos0)=

16 sin²0 - 12 sin0cos0 + 12 sin0cos0 -

9cos²0

= 16sin²0 - 9 cos²0

[tex]\\ \sf\longmapsto (4sin\theta+2cos\theta)(4sin\theta-3cos\theta)[/tex]

[tex]\boxed{\sf (a+b)(a-b)=a^2-b^2}[/tex]

[tex]\\ \sf\longmapsto (4sin\theta)^2-(3cos\theta)^2[/tex]

[tex]\\ \sf\longmapsto 16sin^2\theta-9cos^2\theta[/tex]

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