sukriti009
Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

In a right angled triangle ABC, right angle at A, if AB = 8cm and AC = 6cm, find the value of sinC and cosB.

Sagot :

Answer:

sinC = [tex]\frac{4}{5}[/tex] , cosB = [tex]\frac{4}{5}[/tex]

Step-by-step explanation:

To obtain the ratios we require to find the hypotenuse BC

Using Pythagoras' identity

BC² = AB² + AC² = 8² + 6² = 64 + 36 = 100 ( take square root of both sides )

BC = [tex]\sqrt{100}[/tex] = 10

Then

sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{8}{10}[/tex] = [tex]\frac{4}{5}[/tex]

cosB = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{BC}[/tex]= [tex]\frac{8}{10}[/tex] = [tex]\frac{4}{5}[/tex]

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.