sukriti009
Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

In a right angled triangle ABC, right angle at A, if AB = 8cm and AC = 6cm, find the value of sinC and cosB.

Sagot :

Answer:

sinC = [tex]\frac{4}{5}[/tex] , cosB = [tex]\frac{4}{5}[/tex]

Step-by-step explanation:

To obtain the ratios we require to find the hypotenuse BC

Using Pythagoras' identity

BC² = AB² + AC² = 8² + 6² = 64 + 36 = 100 ( take square root of both sides )

BC = [tex]\sqrt{100}[/tex] = 10

Then

sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{8}{10}[/tex] = [tex]\frac{4}{5}[/tex]

cosB = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{BC}[/tex]= [tex]\frac{8}{10}[/tex] = [tex]\frac{4}{5}[/tex]

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.