sukriti009
Answered

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In a right angled triangle ABC, right angle at A, if AB = 8cm and AC = 6cm, find the value of sinC and cosB.

Sagot :

Answer:

sinC = [tex]\frac{4}{5}[/tex] , cosB = [tex]\frac{4}{5}[/tex]

Step-by-step explanation:

To obtain the ratios we require to find the hypotenuse BC

Using Pythagoras' identity

BC² = AB² + AC² = 8² + 6² = 64 + 36 = 100 ( take square root of both sides )

BC = [tex]\sqrt{100}[/tex] = 10

Then

sinC = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{8}{10}[/tex] = [tex]\frac{4}{5}[/tex]

cosB = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{BC}[/tex]= [tex]\frac{8}{10}[/tex] = [tex]\frac{4}{5}[/tex]

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