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Sagot :
- Focal length=-14cm=f
- Object distance=u=38cm
- Image distance=v
Using lens makers formula
[tex]\\ \tt\longmapsto \dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}[/tex]
[tex]\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}[/tex]
[tex]\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{1}{-14}-\dfrac{1}{38}[/tex]
[tex]\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{-19-7}{266}[/tex]
[tex]\\ \tt\longmapsto \dfrac{1}{v}=\dfrac{-26}{266}[/tex]
[tex]\\ \tt\longmapsto v=\dfrac{266}{-26}[/tex]
[tex]\\ \tt\longmapsto v=\dfrac{133}{-13}[/tex]
[tex]\\ \tt\longmapsto v=-10.2cm[/tex]
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