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Sagot :

Use the way that kids use i.e trial and error method .

Solution:-

The set given by

[tex]\\ \rm\longmapsto \left\{32+n,\dfrac{n}{8},\sqrt{n+225}\right\}[/tex]

Lets understand

  • See the first term any natural value will make it natural .

Come to 2nd one.

  • n should be a multiple of 8 to make it whole.

Come to third one

  • n should be a number which makes the sum a perfect square by which we get a natural no.We have to solve it w.r.t to 2nd one

Lets think

Nearest squares to 225 are 196 and 289

We can't take 196 as we have to take a positive one other wise it will come in terms of i.

Take 289

[tex]\\ \rm\longmapsto n+225=289[/tex]

[tex]\\ \rm\longmapsto n=289-225=64[/tex]

Its divisible by 8 .

Rewrite the set

[tex]\\ \rm\longmapsto \left\{64+32,\dfrac{64}{8},\sqrt{225+64}\right\}[/tex]

[tex]\\ \rm\longmapsto \left\{96,8,\sqrt{289}\right\}[/tex]

[tex]\\ \rm\longmapsto \left\{96,8,17\right\}[/tex]

Hence n=64

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