Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

tính đạo hàm y= ( x^2+1)(X^3+1)(x^4+1)

Sagot :

LammettHash

Use the product and power rules:

[tex]y = (x^2+1)(x^3+1)(x^4+1)[/tex]

The product rule says

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2+1)}{\mathrm dx}(x^3+1)(x^4+1) + (x^2+1)\dfrac{\mathrm d(x^3+1)}{\mathrm dx}(x^4+1) + (x^2+1)(x^3+1)\dfrac{\mathrm d(x^4+1)}{\mathrm dx}[/tex]

and using the power rule to compute the remaining derivatives gives

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \boxed{2x(x^3+1)(x^4+1) + 3x^2(x^2+1)(x^4+1) + 4x^3(x^2+1)(x^3+1)}[/tex]

We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.