At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The height of the building is 3.27 m
Since the question described free-fall under gravity, we will be using the equation for fall under gravity.
Using v² = u² - 2gh where u = initial velocity of toy = 0 m/s (since it is falls from rest), v = final velocity of toy as it hits the ground = 8 m/s, g = acceleration due to gravity = 9.8 m/s² and h = distance the ball falls = height of building
So, making h subject of the formula, we have
h = -(v² - u²)/2g
Substituting the values of the variables into the equation, we have
h = -(v² - u²)/2g
h = -[(8 m/s)² - (0 m/s)²)/(2 × 9.8 m/s²)
h = -(64 m²/s² - 0 m²/s²)/(2 × 9.8 m/s²)
h = -64 m²/s²/19.6 m/s²
h = -3.265 m
h ≅ -3.27 m
The value is negative since we take the top of the building as 0 m and downward direction as negative.
So, the height of the building is 3.27 m
Learn more about free fall here:
https://brainly.com/question/23180622
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.