Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

write in slope intercept form the equasion of the line that is perpendicular to the line y=-1/2x+1 and passes through the point (8,5)

Sagot :

Answer:

y = 2x - 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - [tex]\frac{1}{2}[/tex] x + 1 ← is in slope- intercept form

with slope m = - [tex]\frac{1}{2}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{2} }[/tex] = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (8, 5) into the partial equation

5 = 16 + c ⇒ c = 5 - 16 = - 11

y = 2x - 11 ← equation of perpendicular line