Serinity2022
Answered

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what are the solutions to x^2-5x+3=0?

Sagot :

jcherry99

Answer:

Step-by-step explanation:

You need to use the quadratic equation

x =  [tex]\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}[/tex]

Givens

  • a = 1
  • b = - 5
  • c = 3

x = [tex]\frac{5 +/- \sqrt{5^2 - 4a*1*3} }{2} \\[/tex]

x =( 5 +/- sqrt(25 - 12) ) / 2

x = (5 +/- sqrt(13) )/2

x = (5 + sqrt(13) / 2

x = 4.303  rounded

x = (5 - sqrt(13) ) /2

x = .6972

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