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Enter a balanced equation for the reaction between aqueous lead(II) nitrite and aqueous potassium chloride to form solid lead(II) chloride and aqueous potassium nitrite.

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Answer:

Let's do it like this...

The question says write a balanced equation for the reaction between aqueous lead(II) nitrite and aqueous potassium chloride to form solid lead(II) chloride and aqueous potassium nitrite...

Analysising

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Aqueous Lead(II) Nitrate written as a Formula is Pb(NO3)2 and Aqueous potassium written as a Formula is KOH.......and.......here the statement says they form Solid lead(ll) chloride which is PbCl₂ and aqueous potassium nitrite which is KNOH3

so The unbalanced equation will be

Pb(NO3)2 + KCL ====> PbCl2 + KNOH3

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New Balanced Equation

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Pb(NO3)2 + 2KCL ====> PbCl2 + 2KNOH3

(Balanced) RHS = LHS

Explanation:

Balancing The Equation

Lead (Pb) Has a coefficient of 1 both side.(Balanced)

Nitrate (NO3) has 2 as their coefficient both sides. (balanced)

Potassium (K) has a coefficient of 2 in the left so in the right. (balanced)

Chlorine (Cl) has also a coefficient of 2 in the right so in the left. (balanced)

Therefore the equation is balance the LHS equals to the RHS

NB : There's no any balanced equation than this

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