chaveslizzy
Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

3x+4y=29
6x+5y=43
Solve through elimination

Sagot :

rosa6189

Answer:

Let's solve your system by elimination.

3x+4y=29;6x+5y=43

Multiply the first equation by -2,and multiply the second equation by 1.

−2(3x+4y=29)

1(6x+5y=43)

Becomes:

−6x−8y=−58

6x+5y=43

Add these equations to eliminate x:

−3y=−15

Then solve−3y=−15for y:

−3y=−15

−3y −3 = −15

−3

(Divide both sides by -3)

y=5

Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

3x+4y=29

Substitute5foryin3x+4y=29:

3x+(4)(5)=29

3x+20=29(Simplify both sides of the equation)

3x+20+−20=29+−20(Add -20 to both sides)

3x=9

3x 3 = 9

3

(Divide both sides by 3)

x=3

Answer:

x=3 and y=5

Step-by-step explanation:

I love this stuff 229 999 0523

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.