pie65879
Answered

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f(A)=30000(1-0.2)-2000(t)


f(B)=25000(1-0.1)-1500(t)


25. Graph both equations from question 24 on the graph below. Label both the x- and y-intercepts and the ponits of intersection.



26. Interpret the meaning of both the x- and the y- for each line and the point of intersection.

WILL GIVE BRAINLEST 100Pts From Data Answer All Questions FA300001022000t FB250001011500t 25 Graph Both Equations From Question 24 On The Graph Below Label Both class=
WILL GIVE BRAINLEST 100Pts From Data Answer All Questions FA300001022000t FB250001011500t 25 Graph Both Equations From Question 24 On The Graph Below Label Both class=

Sagot :

mhanifa

Answer:

25.

See the graph attached.

All required points are labeled.

26.

x- intercept is the point when the value of the car drops to zero, after 12 and 15 years respectively.

y- intercept is the point after initial depreciation immediately after sale.

Intersection of the graphs is the point at which the value of each car is same, $18000 after 3 years from sale.

View image mhanifa

Answer:

Step-by-step explanation:

f(A) = 30000 (1 - 0.2) - 2000(t)

f(A) = 30000(0.8) - 2000(t)

f(A) = 24000 - 2000(t)

0 = 24000 - 2000(t)

t = 12

f(B) = 25000(1 - 0.1) - 1500(t)

f(B) = 25000(0.9) - 1500(t)

f(B) = 22500 - 1500(t)

0 = 22500 - 1500(t)

t = 15

22500 - 1500(t) = 24000 - 2000(t)

                 500t = 1500

                        t = 3

22500 - 1500(3) = 18000

26) The y intercepts are the value of the new car when purchased.

The x intercepts are when the car value drops to zero due to depreciation.

The intersection occurs when their depreciated values are equal.

(The intersection does not occur properly on the graph because of camera image distortions)

View image Аноним
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