kyleracrain
Answered

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Which of these equations have no solution? Check all that apply.
a.) 2(x + 2) + 2 = 2(x + 3) + 1
b.) 2x + 3(x + 5) = 5(x – 3)
c.) 4(x + 3) = x + 12
d.) 4 – (2x + 5) = (–4x – 2)
e.) 5(x + 4) – x = 4(x + 5) – 1

Sagot :

zmcever

Answer:

A, B, and C

Step-by-step explanation:

Aichelbee

Answer:

a.) 2(x + 2) + 2 = 2(x + 3) + 1

b.) 2x + 3(x + 5) = 5(x – 3)

e.) 5(x + 4) – x = 4(x + 5) – 1

Step-by-step explanation:

a.) 2(x + 2) + 2 = 2(x + 3) + 1

0 ≠ 1

b.) 2x + 3(x + 5) = 5(x – 3)

0 ≠ -30

c.) 4(x + 3) = x + 12

x = 3

d.) 4 – (2x + 5) = (–4x – 2)

x = -½

e.) 5(x + 4) – x = 4(x + 5) – 1

0 ≠ -1

I hope this helps

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