jonesaudrey028
Answered

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Factor by grouping.
12x³+ 4x²+ 3x + 1​

Sagot :

manissaha129

Answer:

[tex]→12 {x}^{3} + 4 {x}^{2} + 3x + 1 \\ = 4 {x}^{2} (3x + 1) + 1(3x + 1) \\ = \boxed{(3x + 1)(4 {x}^{2} + 1)}✓[/tex]

  • (3x+1)(4x²+1) is the right answer.
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