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A cyclist plans to cover the distance long 240 km. He calculated that if he is going to ride a bike 8.4 km/h faster than planned, he is going to cover that distance 105 minutes earlier. At what speed he originally wanted to cover that distance? ​

Sagot :

olayemiolakunle65

Speed is a rate at which an object moves. In the given question, the original speed is 128.7 km/h.

The speed of an object is the rate at which the object moves. So that:

speed = [tex]\frac{distance}{time}[/tex]

distance = speed x time

Let his original speed be represented by v.

Then:

Distance covered = 240 km

Speed = v + 8.4 km/h

Time = 105 (1.75 hours)

Thus,

240 = (v + 8.4) x 1.75

       = 1.75v + 14.7

240 - 14.7 = 1.75v

v = [tex]\frac{225.3}{1.75}[/tex]

 = 128.743

v = 128.7 km/h

Therefore the original speed to cover that distance is 128.7 km/h.

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